An ellipse is defined in the first quadrant with foci at (c, 0) and (-c, 0). If the equation of the ellipse is x^2/16 + y^2/9 = 1, what are the coordinates of the foci?

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Edzy · Accepted Answer

For the ellipse equation x^2/16 + y^2/9 = 1, we identify a^2 = 16 (a = 4) and b^2 = 9 (b = 3). Now using c^2 = a^2 - b^2 gives c^2 = 16 - 9 = 7, so c = √7, which approximately is 3. The foci are approximately located at (±√7, 0), hence the correct option is (±3, 0).

An ellipse is defined in the first quadrant with foci at (c, 0) and (-c, 0). If the equation of the ellipse is x^2/16 + y^2/9 = 1, what are the coordinates of the foci?

An ellipse is defined in the first quadrant with foci at (c, 0) and (-c, 0). If the equation of the ellipse is x^2/16 + y^2/9 = 1, what are the coordinates of the foci?

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