Single Answer MCQ
Q-00052197
What is the equation of a hyperbola with eccentricity e = 2 and semi-major axis a = 5?
1
x²/25 - y²/20 = 1
2
x²/10 - y²/25 = 1
3
x²/20 - y²/25 = 1
4
x²/25 - y²/50 = 1
Answer and Solution
Answer
B. x²/10 - y²/25 = 1
Solution:
Given e = 2, c = 2a = 10. We find b² = c² - a² = 100 - 25 = 75. The hyperbola is x²/25 - y²/75 = 1.
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