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If y = (x^3 + 2)^(1/x), what is dy/dx using logarithmic differentiation?

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Single Answer MCQ

Q-00103150

dy/dx = (x^3 + 2)^(1/x)((3x^2)/(x^3+2) - (ln(x)/(x^2)))

dy/dx = (x^3 + 2)^(1/x)(3/x^2 + ln(x))

dy/dx = (x^3 + 2)^(1/x)(1/x)

dy/dx = (x^3 + 2)^{1/x - 1}(3x^2)

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