This chapter introduces arithmetic progressions, which are sequences of numbers generated by adding a fixed value to the previous term. Understanding these patterns is crucial for solving real-life mathematical problems.
Arithmetic Progressions – Formula & Equation Sheet
Essential formulas and equations from Mathematics, tailored for Class X in Mathematics.
This one-pager compiles key formulas and equations from the Arithmetic Progressions chapter of Mathematics. Ideal for exam prep, quick reference, and solving time-bound numerical problems accurately.
Key concepts & formulas
Essential formulas, key terms, and important concepts for quick reference and revision.
Formulas
nth term of an AP: aₙ = a + (n - 1)d
aₙ is the nth term, a is the first term, d is the common difference, and n is the term number. This formula helps find any term in an AP. Example: For AP 2, 5, 8,..., the 4th term is 2 + (4-1)*3 = 11.
Sum of first n terms: Sₙ = n/2 [2a + (n - 1)d]
Sₙ is the sum of first n terms, a is the first term, d is the common difference. It calculates the total of first n terms. Tip: Also expressible as Sₙ = n/2 (a + l), where l is the last term.
Common difference: d = aₙ - aₙ₋₁
d is the common difference, aₙ is the nth term, aₙ₋₁ is the (n-1)th term. It finds the difference between consecutive terms. Example: In 3, 7, 11,..., d = 7 - 3 = 4.
Number of terms: n = [(l - a)/d] + 1
n is the number of terms, l is the last term, a is the first term, d is the common difference. Useful when first term, last term, and common difference are known.
Arithmetic Mean: AM = (a + b)/2
AM is the arithmetic mean between two numbers a and b. It’s the middle term in an AP of three terms. Example: AM of 4 and 6 is (4+6)/2 = 5.
Sum when first and last terms are known: Sₙ = n/2 (a + l)
Sₙ is the sum of first n terms, a is the first term, l is the last term. Simplifies calculation when the last term is known.
General form of an AP: a, a + d, a + 2d, ..., a + (n-1)d
Represents the sequence of an AP where each term increases by a common difference d. Example: 5, 9, 13,... where a=5, d=4.
Difference of sums: Sₙ - Sₙ₋₁ = aₙ
The difference between the sum of first n terms and first (n-1) terms gives the nth term. Useful for verifying terms.
Sum of natural numbers: Sₙ = n(n + 1)/2
Special case of AP sum where a=1, d=1. Example: Sum of first 5 natural numbers is 5*6/2 = 15.
Condition for three terms to be in AP: 2b = a + c
For three terms a, b, c to be in AP, twice the middle term must equal the sum of the first and last terms. Example: 3, 7, 11 are in AP as 2*7 = 3 + 11.
Equations
Finding d: d = (aₙ - a₁)/(n - 1)
Calculates common difference d using the first term a₁, nth term aₙ, and number of terms n. Example: For AP with a₁=3, a₅=11, d=(11-3)/(5-1)=2.
Finding n: n = 1 + (aₙ - a)/d
Determines the term number n using the nth term aₙ, first term a, and common difference d. Example: For a=2, d=3, aₙ=14, n=1+(14-2)/3=5.
Sum of terms from mth to nth: S = Sₙ - Sₘ₋₁
Calculates the sum of terms from the mth to the nth term by subtracting the sum up to (m-1)th term from the sum up to nth term.
Last term from sum: l = (2Sₙ)/n - a
Finds the last term l when sum Sₙ, number of terms n, and first term a are known. Rearranged from Sₙ = n/2 (a + l).
First term from sum: a = (2Sₙ)/n - l
Finds the first term a when sum Sₙ, number of terms n, and last term l are known. Derived from Sₙ = n/2 (a + l).
Middle term in odd number of terms: aₘ = Sₙ/n
For an AP with odd number of terms n, the middle term is the average of the sum. Example: For AP 4,7,10,13,16, S₅=50, middle term a₃=50/5=10.
Sum of first n odd numbers: Sₙ = n²
Special case where the sum of first n odd numbers (1,3,5,...) equals n². Example: Sum of first 3 odd numbers is 1+3+5=9=3².
Sum of first n even numbers: Sₙ = n(n + 1)
Special case where the sum of first n even numbers (2,4,6,...) equals n(n+1). Example: Sum of first 4 even numbers is 2+4+6+8=20=4*5.
Product of equidistant terms in finite AP: a₁ * aₙ = a₂ * aₙ₋₁ = ...
In a finite AP, the product of terms equidistant from the start and end are equal. Useful for problems involving product of terms.
Condition for AP: aₖ₊₁ - aₖ = constant
A sequence is an AP if the difference between consecutive terms is constant. This is the defining property of an AP.
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